The Normality Calculator is a free online tool for determining the normality of a chemical solution. The online normality calculator tool speeds up the calculation and displays the solution's normality in a matter of seconds.
Normality Calculator: Have you ever stuck up finding the concentration of a chemical solution? If so, make use of our handy tool Normality Calculator and find the chemical solution concentration in no time. Go through the later modules to find out what is meant by Normality, Normality Formulas, Relationship between Normality and Molarity, Uses and Limitations of Normality, Solved Examples on Calculating the Normality, etc. all in detail.
most commonly used to calculate the concentration of a solution, which is equal to the ratio of gramme equivalent weight to litres of solution.
According to the standard definition, normality is defined as the number of grammes of mole equivalents of solute contained in one litre of a solution. The amount of moles of reactive units in a chemical is what we mean when we say equivalent.
There are different formulas to measure the Normality given the other parameters. We have mentioned all of them for your knowledge below and they are as such
Number of gram equivalents = weight of solute / [Equivalent weight of solute]
The normality calculator can be used in the following way
Normality and Molarity are the commonly used expressions in chemistry. Both of them denote the quantitative measurement of a substance.
The formula for Molarity is Molarity (M) = No. of moles of solute × [volume of the solution in litres]-1
Normality = [Molarity × Molar mass] × [Equivalent mass]-1
Normality = Molarity × Basicity
Normality = Molarity × Acidity
N = M × number of equivalents
Normality is used in three different situations and go through them below
Example 1: What are the chances that the following is normal: 0.1381 M NaOH and 0.0521 M H3PO4
N = 0.1381 mol/L × (1 eq/1mol)
Which is = 0.1381 eq/L
= 0.1381 N
N = 0.0521 mol/L × (3 eq/1mol)
= 0.156 N
Example 2: Calculate and find the normalcy in the following reaction.1.0 M H3PO4
H3AsO4 + 2NaOH → Na2HAsO4 + 2H2O
When we examine the reaction, we can see that just two of the H+ ions in H3AsO4 react with NaOH to produce the result. As a result, the two ions have two equivalents. We shall use the given formula to determine normality.
N = Molarity (M) × no. of equivalents
N = 1.0 × 2 (replacing the values)
As a result, the solution's normality is = 2.0.
1. What is meant by Normality?
Normality is used to determine the equivalent concentration of a solution.
2. What is the formula to calculate Normality?
The formula to calculate Normality is N = weight of solute/(volume of solvent x equivalent weight).
Moles = mass of the substance in grams/molecular weight.
3. What is the relation between Normality and Molarity?
The Relation between Normality and Molarity is given by the expression Normality = [Molarity × Molar mass] × [Equivalent mass]^-1